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Determine Nearest DayUsers of an application can retrieve sales between 2 dates that they pick in the front end (DateFrom & DateTo) I have sales data that these values will be used to query, the data is always summarised to the Sunday of each week. Before my stored procedure attempts to query, it needs to work out the nearest Sunday for each of the dates. Eg; DateFrom = 14th December 2005 This date needs to be converted to look 'backwards' for the nearest Sunday. It needs to find 11th December. DateTo = 29th December 2005 This needs to be converted forwards to look to the nearest Sunday. It needs to find 01 Jan 2006. Is there any TSQL that can be used to work this out, or is it a case of using a lookup table (which I do have available) Thanks Dylan Hi
DECLARE @Today datetime SET @Today = '20060105' SELECT DATEADD(day, DATEDIFF(day, '1900', @Today)/7*7+6 , '1900') Show quote "DylanM" <Dyl***@discussions.microsoft.com> wrote in message news:031DC14C-596B-411C-B15D-88D17743AB7E@microsoft.com... > Hi, > > Users of an application can retrieve sales between 2 dates that they pick > in > the front end (DateFrom & DateTo) > > I have sales data that these values will be used to query, the data is > always summarised to the Sunday of each week. > > Before my stored procedure attempts to query, it needs to work out the > nearest Sunday for each of the dates. Eg; > > DateFrom = 14th December 2005 > This date needs to be converted to look 'backwards' for the nearest > Sunday. > It needs to find 11th December. > > DateTo = 29th December 2005 > This needs to be converted forwards to look to the nearest Sunday. It > needs > to find 01 Jan 2006. > > Is there any TSQL that can be used to work this out, or is it a case of > using a lookup table (which I do have available) > > > Thanks > Dylan > Excellent, thanks Uri.
And to convert backwards, I thinks it's just as follows...?? (-1 instead of +6) SELECT DATEADD(day, DATEDIFF(day, '1900', @Today)/7*7-1 , '1900') Thanks again. Show quote "Uri Dimant" wrote: > Hi > DECLARE @Today datetime > SET @Today = '20060105' > > SELECT DATEADD(day, DATEDIFF(day, '1900', @Today)/7*7+6 , '1900') > > > > This rounds it up to the nearest Sunday. It prints DateTo, the day or the
week dateto is, and then the rounded up date, and the day of the week the rounded up day is. I suspect you can use the modulus operator to make this perform better, but I'm not SK. create table salesData (pk int not null identity primary key, DateTo datetime, DateFrom Datetime) GO insert into salesData values (getdate()-101,getdate()-103) insert into salesData values (getdate()-105,getdate()-108) GO select case when DATENAME ( dw , DateTo )='Sunday' then dateto when DATENAME ( dw , DateTo )='Monday' then dateto-1 when DATENAME ( dw , DateTo )='Tuesday' then dateto-2 when DATENAME ( dw , DateTo )='Wednesday' then dateto-3 when DATENAME ( dw , DateTo )='Thursday' then dateto-4 when DATENAME ( dw , DateTo )='Friday' then dateto-5 when DATENAME ( dw , DateTo )='Saturday' then dateto-6 end, dateto, datename(weekday,dateto), case when DATENAME ( dw , DateTo )='Sunday' then datename(weekday, dateto) when DATENAME ( dw , DateTo )='Monday' then datename(weekday, dateto-1) when DATENAME ( dw , DateTo )='Tuesday' then datename(weekday, dateto-2) when DATENAME ( dw , DateTo )='Wednesday' then datename(weekday, dateto-3) when DATENAME ( dw , DateTo )='Thursday' then datename(weekday, dateto-4) when DATENAME ( dw , DateTo )='Friday' then datename(weekday, dateto-5) when DATENAME ( dw , DateTo )='Saturday' then datename(weekday, dateto-6) end from salesdata go drop table salesdata go -- Show quoteHilary Cotter Looking for a SQL Server replication book? http://www.nwsu.com/0974973602.html Looking for a FAQ on Indexing Services/SQL FTS http://www.indexserverfaq.com "DylanM" <Dyl***@discussions.microsoft.com> wrote in message news:031DC14C-596B-411C-B15D-88D17743AB7E@microsoft.com... > Hi, > > Users of an application can retrieve sales between 2 dates that they pick > in > the front end (DateFrom & DateTo) > > I have sales data that these values will be used to query, the data is > always summarised to the Sunday of each week. > > Before my stored procedure attempts to query, it needs to work out the > nearest Sunday for each of the dates. Eg; > > DateFrom = 14th December 2005 > This date needs to be converted to look 'backwards' for the nearest > Sunday. > It needs to find 11th December. > > DateTo = 29th December 2005 > This needs to be converted forwards to look to the nearest Sunday. It > needs > to find 01 Jan 2006. > > Is there any TSQL that can be used to work this out, or is it a case of > using a lookup table (which I do have available) > > > Thanks > Dylan > To do it in one shot, try this:
SELECT DATEADD(day, DATEDIFF(day, '18991231', @Today+3)/7*7 , '18991231') It will find "next" Sunday, if today is Thursday, Friday, or Saturday, it will find "This" Sunday if today is Sunday, and it will find "last" Sunday if today is Monday, Tuesday, or Wednesday. Steve Kass Drew Unviersity DylanM wrote: Show quote >Hi, > >Users of an application can retrieve sales between 2 dates that they pick in >the front end (DateFrom & DateTo) > >I have sales data that these values will be used to query, the data is >always summarised to the Sunday of each week. > >Before my stored procedure attempts to query, it needs to work out the >nearest Sunday for each of the dates. Eg; > >DateFrom = 14th December 2005 >This date needs to be converted to look 'backwards' for the nearest Sunday. >It needs to find 11th December. > >DateTo = 29th December 2005 >This needs to be converted forwards to look to the nearest Sunday. It needs >to find 01 Jan 2006. > >Is there any TSQL that can be used to work this out, or is it a case of >using a lookup table (which I do have available) > > >Thanks >Dylan > > > |
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