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T-SQL QuestionI need to execute a sql
Select (A.JanSalary * 20) as JanSal, (A.FebSalary * 20) as FebSal, (A.MarSalary * 20) as MarSal, (A.AprSalary * 20) as AprSal, sum(JanSal + FebSal + MarSal + AprSal) as 'Total' From MyTable A Error message - 'Invalid column JanSal,.....' Question is - How to use the computed column in the same SELECT statement ?? Thanks Mike You can use a derived table:
select x.* , (JanSal + FebSal + MarSal + AprSal) as Total from ( Select (A.JanSalary * 20) as JanSal, (A.FebSalary * 20) as FebSal, (A.MarSalary * 20) as MarSal, (A.AprSalary * 20) as AprSal From MyTable A ) x -- Tom ---------------------------------------------------- Thomas A. Moreau, BSc, PhD, MCSE, MCDBA SQL Server MVP Columnist, SQL Server Professional Toronto, ON Canada www.pinpub.com .. "MS User" <sql***@sql.com> wrote in message I need to execute a sqlnews:utEqCURpFHA.3516@TK2MSFTNGP15.phx.gbl... Select (A.JanSalary * 20) as JanSal, (A.FebSalary * 20) as FebSal, (A.MarSalary * 20) as MarSal, (A.AprSalary * 20) as AprSal, sum(JanSal + FebSal + MarSal + AprSal) as 'Total' From MyTable A Error message - 'Invalid column JanSal,.....' Question is - How to use the computed column in the same SELECT statement ?? Thanks Mike Error Message
Server: Msg 8155, Level 16, State 2, Line 1 No column was specified for column 2 of 'X'. Here is my actual SQL SELECT round(sum(Jan06 + Feb06 + Mar06 + Apr06 + May06 + Jun06 + Jul06 + Aug06 + Sep06 + Oct06 + Nov06 + Dec06), 1) as TotalOrAvg from (SELECT BDC.departmentCode , BDC.departmentCode + '-' + BDC.departmentName, round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( JanOTHours ) * (1 + PayIncreaseJan)),1) as Jan06, round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( FebOTHours ) * (1 + PayIncreaseFeb)),1) as Feb06, round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( MarOTHours ) * (1 + PayIncreaseMar)),1) as Mar06, round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( AprOTHours ) * (1 + PayIncreaseApr)),1) as Apr06, round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( MayOTHours ) * (1 + PayIncreaseMay)),1) as May06, round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( JunOTHours ) * (1 + PayIncreaseJun)),1) as Jun06, round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( JulOTHours ) * (1 + PayIncreaseJul)),1) as Jul06, round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( AugOTHours ) * (1 + PayIncreaseAug)),1) as Aug06, round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( SepOTHours ) * (1 + PayIncreaseSep)),1) as Sep06, round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( OctOTHours ) * (1 + PayIncreaseOct)),1) as Oct06, round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( NovOTHours ) * (1 + PayIncreaseNov)),1) as Nov06, round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( DecOTHours ) * (1 + PayIncreaseDec)),1) as Dec06 FROM BudgetEmployeeAssignment BEA LEFT OUTER JOIN BudgetEmployeeDataBudget BED ON BED.UniqueID = BEA.UniqueID and BEA.AllocatedRoad = @road RIGHT JOIN BudgetDepartmentCodes BDC ON BDC.DepartmentCode = BEA.AllocatedDept and BED.Deleted = 'N' GROUP BY BDC.DepartmentCode, BDC.DepartmentName ) X Show quote "Tom Moreau" <tom@dont.spam.me.cips.ca> wrote in message news:uMaa2wRpFHA.3316@TK2MSFTNGP14.phx.gbl... > You can use a derived table: > > select > x.* > , (JanSal + FebSal + MarSal + AprSal) as Total > from > ( > Select (A.JanSalary * 20) as JanSal, > (A.FebSalary * 20) as FebSal, > (A.MarSalary * 20) as MarSal, > (A.AprSalary * 20) as AprSal > From MyTable A > ) x > > -- > Tom > > ---------------------------------------------------- > Thomas A. Moreau, BSc, PhD, MCSE, MCDBA > SQL Server MVP > Columnist, SQL Server Professional > Toronto, ON Canada > www.pinpub.com > . > "MS User" <sql***@sql.com> wrote in message > news:utEqCURpFHA.3516@TK2MSFTNGP15.phx.gbl... > I need to execute a sql > > Select (A.JanSalary * 20) as JanSal, > (A.FebSalary * 20) as FebSal, > (A.MarSalary * 20) as MarSal, > (A.AprSalary * 20) as AprSal, > sum(JanSal + FebSal + MarSal + AprSal) as 'Total' > From MyTable A > > > Error message - 'Invalid column JanSal,.....' > > Question is - How to use the computed column in the same SELECT statement > ?? > > Thanks > Mike > > Hi
The error message tells you exactly what is wrong. The line: BDC.departmentCode + '-' + BDC.departmentName, needs an alias say BDC.departmentCode + '-' + BDC.departmentName AS FulldepartmentName, Although there is no point in having the line at all if you don't use it! John Show quote "MS User" <sql***@sql.com> wrote in message news:%23m64UpgpFHA.1148@TK2MSFTNGP12.phx.gbl... > Error Message > > Server: Msg 8155, Level 16, State 2, Line 1 > No column was specified for column 2 of 'X'. > > > Here is my actual SQL > > SELECT round(sum(Jan06 + Feb06 + Mar06 + Apr06 + May06 + Jun06 + Jul06 + > Aug06 + Sep06 + Oct06 + Nov06 + Dec06), 1) as TotalOrAvg > from > (SELECT > BDC.departmentCode , > BDC.departmentCode + '-' + BDC.departmentName, > round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > JanOTHours ) * (1 + PayIncreaseJan)),1) as Jan06, > round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > FebOTHours ) * (1 + PayIncreaseFeb)),1) as Feb06, > round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > MarOTHours ) * (1 + PayIncreaseMar)),1) as Mar06, > round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > AprOTHours ) * (1 + PayIncreaseApr)),1) as Apr06, > round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > MayOTHours ) * (1 + PayIncreaseMay)),1) as May06, > round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > JunOTHours ) * (1 + PayIncreaseJun)),1) as Jun06, > round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > JulOTHours ) * (1 + PayIncreaseJul)),1) as Jul06, > round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > AugOTHours ) * (1 + PayIncreaseAug)),1) as Aug06, > round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > SepOTHours ) * (1 + PayIncreaseSep)),1) as Sep06, > round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > OctOTHours ) * (1 + PayIncreaseOct)),1) as Oct06, > round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > NovOTHours ) * (1 + PayIncreaseNov)),1) as Nov06, > round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > DecOTHours ) * (1 + PayIncreaseDec)),1) as Dec06 > > FROM BudgetEmployeeAssignment BEA > LEFT OUTER JOIN BudgetEmployeeDataBudget BED > ON BED.UniqueID = BEA.UniqueID and > BEA.AllocatedRoad = @road > RIGHT JOIN BudgetDepartmentCodes BDC > ON BDC.DepartmentCode = BEA.AllocatedDept and BED.Deleted = 'N' > GROUP BY BDC.DepartmentCode, > BDC.DepartmentName > ) X > > > > "Tom Moreau" <tom@dont.spam.me.cips.ca> wrote in message > news:uMaa2wRpFHA.3316@TK2MSFTNGP14.phx.gbl... >> You can use a derived table: >> >> select >> x.* >> , (JanSal + FebSal + MarSal + AprSal) as Total >> from >> ( >> Select (A.JanSalary * 20) as JanSal, >> (A.FebSalary * 20) as FebSal, >> (A.MarSalary * 20) as MarSal, >> (A.AprSalary * 20) as AprSal >> From MyTable A >> ) x >> >> -- >> Tom >> >> ---------------------------------------------------- >> Thomas A. Moreau, BSc, PhD, MCSE, MCDBA >> SQL Server MVP >> Columnist, SQL Server Professional >> Toronto, ON Canada >> www.pinpub.com >> . >> "MS User" <sql***@sql.com> wrote in message >> news:utEqCURpFHA.3516@TK2MSFTNGP15.phx.gbl... >> I need to execute a sql >> >> Select (A.JanSalary * 20) as JanSal, >> (A.FebSalary * 20) as FebSal, >> (A.MarSalary * 20) as MarSal, >> (A.AprSalary * 20) as AprSal, >> sum(JanSal + FebSal + MarSal + AprSal) as 'Total' >> From MyTable A >> >> >> Error message - 'Invalid column JanSal,.....' >> >> Question is - How to use the computed column in the same SELECT statement >> ?? >> >> Thanks >> Mike >> >> > > Thanks
But now its returning only the 'TotalOrAvg ' but NOT the other columns (Jan06, Feb06.......) Mike Show quote "John Bell" <jbellnewspo***@hotmail.com> wrote in message news:uIPGsWhpFHA.1996@TK2MSFTNGP10.phx.gbl... > Hi > > The error message tells you exactly what is wrong. > > The line: > > BDC.departmentCode + '-' + BDC.departmentName, > > needs an alias say > > BDC.departmentCode + '-' + BDC.departmentName AS FulldepartmentName, > > Although there is no point in having the line at all if you don't use it! > > John > > > "MS User" <sql***@sql.com> wrote in message > news:%23m64UpgpFHA.1148@TK2MSFTNGP12.phx.gbl... >> Error Message >> >> Server: Msg 8155, Level 16, State 2, Line 1 >> No column was specified for column 2 of 'X'. >> >> >> Here is my actual SQL >> >> SELECT round(sum(Jan06 + Feb06 + Mar06 + Apr06 + May06 + Jun06 + Jul06 + >> Aug06 + Sep06 + Oct06 + Nov06 + Dec06), 1) as TotalOrAvg >> from >> (SELECT >> BDC.departmentCode , >> BDC.departmentCode + '-' + BDC.departmentName, >> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >> JanOTHours ) * (1 + PayIncreaseJan)),1) as Jan06, >> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >> FebOTHours ) * (1 + PayIncreaseFeb)),1) as Feb06, >> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >> MarOTHours ) * (1 + PayIncreaseMar)),1) as Mar06, >> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >> AprOTHours ) * (1 + PayIncreaseApr)),1) as Apr06, >> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >> MayOTHours ) * (1 + PayIncreaseMay)),1) as May06, >> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >> JunOTHours ) * (1 + PayIncreaseJun)),1) as Jun06, >> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >> JulOTHours ) * (1 + PayIncreaseJul)),1) as Jul06, >> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >> AugOTHours ) * (1 + PayIncreaseAug)),1) as Aug06, >> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >> SepOTHours ) * (1 + PayIncreaseSep)),1) as Sep06, >> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >> OctOTHours ) * (1 + PayIncreaseOct)),1) as Oct06, >> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >> NovOTHours ) * (1 + PayIncreaseNov)),1) as Nov06, >> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >> DecOTHours ) * (1 + PayIncreaseDec)),1) as Dec06 >> >> FROM BudgetEmployeeAssignment BEA >> LEFT OUTER JOIN BudgetEmployeeDataBudget BED >> ON BED.UniqueID = BEA.UniqueID and >> BEA.AllocatedRoad = @road >> RIGHT JOIN BudgetDepartmentCodes BDC >> ON BDC.DepartmentCode = BEA.AllocatedDept and BED.Deleted = 'N' >> GROUP BY BDC.DepartmentCode, >> BDC.DepartmentName >> ) X >> >> >> >> "Tom Moreau" <tom@dont.spam.me.cips.ca> wrote in message >> news:uMaa2wRpFHA.3316@TK2MSFTNGP14.phx.gbl... >>> You can use a derived table: >>> >>> select >>> x.* >>> , (JanSal + FebSal + MarSal + AprSal) as Total >>> from >>> ( >>> Select (A.JanSalary * 20) as JanSal, >>> (A.FebSalary * 20) as FebSal, >>> (A.MarSalary * 20) as MarSal, >>> (A.AprSalary * 20) as AprSal >>> From MyTable A >>> ) x >>> >>> -- >>> Tom >>> >>> ---------------------------------------------------- >>> Thomas A. Moreau, BSc, PhD, MCSE, MCDBA >>> SQL Server MVP >>> Columnist, SQL Server Professional >>> Toronto, ON Canada >>> www.pinpub.com >>> . >>> "MS User" <sql***@sql.com> wrote in message >>> news:utEqCURpFHA.3516@TK2MSFTNGP15.phx.gbl... >>> I need to execute a sql >>> >>> Select (A.JanSalary * 20) as JanSal, >>> (A.FebSalary * 20) as FebSal, >>> (A.MarSalary * 20) as MarSal, >>> (A.AprSalary * 20) as AprSal, >>> sum(JanSal + FebSal + MarSal + AprSal) as 'Total' >>> From MyTable A >>> >>> >>> Error message - 'Invalid column JanSal,.....' >>> >>> Question is - How to use the computed column in the same SELECT >>> statement ?? >>> >>> Thanks >>> Mike >>> >>> >> >> > > Error Message
Server: Msg 8118, Level 16, State 1, Line 1 Column 'X.departmentCode' is invalid in the select list because it is not contained in an aggregate function and there is no GROUP BY clause. Server: Msg 8118, Level 16, State 1, Line 1 Column 'X.FulldepartmentName' is invalid in the select list because it is not contained in an aggregate function and there is no GROUP BY clause. Server: Msg 8118, Level 16, State 1, Line 1 Column 'X.Jan06' is invalid in the select list because it is not contained in an aggregate function and there is no GROUP BY clause. Server: Msg 8118, Level 16, State 1, Line 1 Column 'X.Feb06' is invalid in the select list because it is not contained in an aggregate function and there is no GROUP BY clause. SELECT X.*, round(sum(Jan06 + Feb06), 1) as TotalOrAvg from (SELECT BDC.departmentCode , BDC.departmentCode + '-' + BDC.departmentName as FulldepartmentName, round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( JanOTHours ) * (1 + PayIncreaseJan)),1) as Jan06, round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( FebOTHours ) * (1 + PayIncreaseFeb)),1) as Feb06 FROM BudgetEmployeeAssignment BEA LEFT OUTER JOIN BudgetEmployeeDataBudget BED ON BED.UniqueID = BEA.UniqueID and BEA.AllocatedRoad = 'necr' RIGHT JOIN BudgetDepartmentCodes BDC ON BDC.DepartmentCode = BEA.AllocatedDept and BED.Deleted = 'N' GROUP BY BDC.DepartmentCode, BDC.DepartmentName ) X Show quote "MS User" <sql***@sql.com> wrote in message news:epP3LampFHA.3516@TK2MSFTNGP15.phx.gbl... > Thanks > > But now its returning only the 'TotalOrAvg ' but NOT the other columns > (Jan06, Feb06.......) > > > Mike > > "John Bell" <jbellnewspo***@hotmail.com> wrote in message > news:uIPGsWhpFHA.1996@TK2MSFTNGP10.phx.gbl... >> Hi >> >> The error message tells you exactly what is wrong. >> >> The line: >> >> BDC.departmentCode + '-' + BDC.departmentName, >> >> needs an alias say >> >> BDC.departmentCode + '-' + BDC.departmentName AS FulldepartmentName, >> >> Although there is no point in having the line at all if you don't use it! >> >> John >> >> >> "MS User" <sql***@sql.com> wrote in message >> news:%23m64UpgpFHA.1148@TK2MSFTNGP12.phx.gbl... >>> Error Message >>> >>> Server: Msg 8155, Level 16, State 2, Line 1 >>> No column was specified for column 2 of 'X'. >>> >>> >>> Here is my actual SQL >>> >>> SELECT round(sum(Jan06 + Feb06 + Mar06 + Apr06 + May06 + Jun06 + Jul06 >>> + Aug06 + Sep06 + Oct06 + Nov06 + Dec06), 1) as TotalOrAvg >>> from >>> (SELECT >>> BDC.departmentCode , >>> BDC.departmentCode + '-' + BDC.departmentName, >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >>> JanOTHours ) * (1 + PayIncreaseJan)),1) as Jan06, >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >>> FebOTHours ) * (1 + PayIncreaseFeb)),1) as Feb06, >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >>> MarOTHours ) * (1 + PayIncreaseMar)),1) as Mar06, >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >>> AprOTHours ) * (1 + PayIncreaseApr)),1) as Apr06, >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >>> MayOTHours ) * (1 + PayIncreaseMay)),1) as May06, >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >>> JunOTHours ) * (1 + PayIncreaseJun)),1) as Jun06, >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >>> JulOTHours ) * (1 + PayIncreaseJul)),1) as Jul06, >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >>> AugOTHours ) * (1 + PayIncreaseAug)),1) as Aug06, >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >>> SepOTHours ) * (1 + PayIncreaseSep)),1) as Sep06, >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >>> OctOTHours ) * (1 + PayIncreaseOct)),1) as Oct06, >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >>> NovOTHours ) * (1 + PayIncreaseNov)),1) as Nov06, >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( >>> DecOTHours ) * (1 + PayIncreaseDec)),1) as Dec06 >>> >>> FROM BudgetEmployeeAssignment BEA >>> LEFT OUTER JOIN BudgetEmployeeDataBudget BED >>> ON BED.UniqueID = BEA.UniqueID and >>> BEA.AllocatedRoad = @road >>> RIGHT JOIN BudgetDepartmentCodes BDC >>> ON BDC.DepartmentCode = BEA.AllocatedDept and BED.Deleted = 'N' >>> GROUP BY BDC.DepartmentCode, >>> BDC.DepartmentName >>> ) X >>> >>> >>> >>> "Tom Moreau" <tom@dont.spam.me.cips.ca> wrote in message >>> news:uMaa2wRpFHA.3316@TK2MSFTNGP14.phx.gbl... >>>> You can use a derived table: >>>> >>>> select >>>> x.* >>>> , (JanSal + FebSal + MarSal + AprSal) as Total >>>> from >>>> ( >>>> Select (A.JanSalary * 20) as JanSal, >>>> (A.FebSalary * 20) as FebSal, >>>> (A.MarSalary * 20) as MarSal, >>>> (A.AprSalary * 20) as AprSal >>>> From MyTable A >>>> ) x >>>> >>>> -- >>>> Tom >>>> >>>> ---------------------------------------------------- >>>> Thomas A. Moreau, BSc, PhD, MCSE, MCDBA >>>> SQL Server MVP >>>> Columnist, SQL Server Professional >>>> Toronto, ON Canada >>>> www.pinpub.com >>>> . >>>> "MS User" <sql***@sql.com> wrote in message >>>> news:utEqCURpFHA.3516@TK2MSFTNGP15.phx.gbl... >>>> I need to execute a sql >>>> >>>> Select (A.JanSalary * 20) as JanSal, >>>> (A.FebSalary * 20) as FebSal, >>>> (A.MarSalary * 20) as MarSal, >>>> (A.AprSalary * 20) as AprSal, >>>> sum(JanSal + FebSal + MarSal + AprSal) as 'Total' >>>> From MyTable A >>>> >>>> >>>> Error message - 'Invalid column JanSal,.....' >>>> >>>> Question is - How to use the computed column in the same SELECT >>>> statement ?? >>>> >>>> Thanks >>>> Mike >>>> >>>> >>> >>> >> >> > > You don't need SUM in the outer select, since the sums are already computed
in the derived table. SELECT X.*, round(Jan06 + Feb06 /* + ... */, 1) AS TotalOrAvg You cannot mix columns and aggregate functions in the select list unless you have a GROUP BY clause. Show quote "MS User" <sql***@sql.com> wrote in message news:#6bMrrmpFHA.3156@TK2MSFTNGP10.phx.gbl... > Error Message > > Server: Msg 8118, Level 16, State 1, Line 1 > Column 'X.departmentCode' is invalid in the select list because it is not > contained in an aggregate function and there is no GROUP BY clause. > Server: Msg 8118, Level 16, State 1, Line 1 > Column 'X.FulldepartmentName' is invalid in the select list because it is > not contained in an aggregate function and there is no GROUP BY clause. > Server: Msg 8118, Level 16, State 1, Line 1 > Column 'X.Jan06' is invalid in the select list because it is not contained > in an aggregate function and there is no GROUP BY clause. > Server: Msg 8118, Level 16, State 1, Line 1 > Column 'X.Feb06' is invalid in the select list because it is not contained > in an aggregate function and there is no GROUP BY clause. > > > SELECT X.*, > round(sum(Jan06 + Feb06), 1) as TotalOrAvg > from > (SELECT > BDC.departmentCode , > BDC.departmentCode + '-' + BDC.departmentName as FulldepartmentName, > round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > JanOTHours ) * (1 + PayIncreaseJan)),1) as Jan06, > round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > FebOTHours ) * (1 + PayIncreaseFeb)),1) as Feb06 > FROM BudgetEmployeeAssignment BEA > LEFT OUTER JOIN BudgetEmployeeDataBudget BED > ON BED.UniqueID = BEA.UniqueID and > BEA.AllocatedRoad = 'necr' > RIGHT JOIN BudgetDepartmentCodes BDC > ON BDC.DepartmentCode = BEA.AllocatedDept and BED.Deleted = 'N' > GROUP BY BDC.DepartmentCode, > BDC.DepartmentName > > ) X > > > > > > > "MS User" <sql***@sql.com> wrote in message > news:epP3LampFHA.3516@TK2MSFTNGP15.phx.gbl... > > Thanks > > > > But now its returning only the 'TotalOrAvg ' but NOT the other columns > > (Jan06, Feb06.......) > > > > > > Mike > > > > "John Bell" <jbellnewspo***@hotmail.com> wrote in message > > news:uIPGsWhpFHA.1996@TK2MSFTNGP10.phx.gbl... > >> Hi > >> > >> The error message tells you exactly what is wrong. > >> > >> The line: > >> > >> BDC.departmentCode + '-' + BDC.departmentName, > >> > >> needs an alias say > >> > >> BDC.departmentCode + '-' + BDC.departmentName AS FulldepartmentName, > >> > >> Although there is no point in having the line at all if you don't use it! > >> > >> John > >> > >> > >> "MS User" <sql***@sql.com> wrote in message > >> news:%23m64UpgpFHA.1148@TK2MSFTNGP12.phx.gbl... > >>> Error Message > >>> > >>> Server: Msg 8155, Level 16, State 2, Line 1 > >>> No column was specified for column 2 of 'X'. > >>> > >>> > >>> Here is my actual SQL > >>> > >>> SELECT round(sum(Jan06 + Feb06 + Mar06 + Apr06 + May06 + Jun06 + Jul06 > >>> + Aug06 + Sep06 + Oct06 + Nov06 + Dec06), 1) as TotalOrAvg > >>> from > >>> (SELECT > >>> BDC.departmentCode , > >>> BDC.departmentCode + '-' + BDC.departmentName, > >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > >>> JanOTHours ) * (1 + PayIncreaseJan)),1) as Jan06, > >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > >>> FebOTHours ) * (1 + PayIncreaseFeb)),1) as Feb06, > >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > >>> MarOTHours ) * (1 + PayIncreaseMar)),1) as Mar06, > >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > >>> AprOTHours ) * (1 + PayIncreaseApr)),1) as Apr06, > >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > >>> MayOTHours ) * (1 + PayIncreaseMay)),1) as May06, > >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > >>> JunOTHours ) * (1 + PayIncreaseJun)),1) as Jun06, > >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > >>> JulOTHours ) * (1 + PayIncreaseJul)),1) as Jul06, > >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > >>> AugOTHours ) * (1 + PayIncreaseAug)),1) as Aug06, > >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > >>> SepOTHours ) * (1 + PayIncreaseSep)),1) as Sep06, > >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > >>> OctOTHours ) * (1 + PayIncreaseOct)),1) as Oct06, > >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > >>> NovOTHours ) * (1 + PayIncreaseNov)),1) as Nov06, > >>> round(sum((BEA.PercentAssigned/100.0)* (BED.WageHourly * 1.5) * ( > >>> DecOTHours ) * (1 + PayIncreaseDec)),1) as Dec06 > >>> > >>> FROM BudgetEmployeeAssignment BEA > >>> LEFT OUTER JOIN BudgetEmployeeDataBudget BED > >>> ON BED.UniqueID = BEA.UniqueID and > >>> BEA.AllocatedRoad = @road > >>> RIGHT JOIN BudgetDepartmentCodes BDC > >>> ON BDC.DepartmentCode = BEA.AllocatedDept and BED.Deleted = 'N' > >>> GROUP BY BDC.DepartmentCode, > >>> BDC.DepartmentName > >>> ) X > >>> > >>> > >>> > >>> "Tom Moreau" <tom@dont.spam.me.cips.ca> wrote in message > >>> news:uMaa2wRpFHA.3316@TK2MSFTNGP14.phx.gbl... > >>>> You can use a derived table: > >>>> > >>>> select > >>>> x.* > >>>> , (JanSal + FebSal + MarSal + AprSal) as Total > >>>> from > >>>> ( > >>>> Select (A.JanSalary * 20) as JanSal, > >>>> (A.FebSalary * 20) as FebSal, > >>>> (A.MarSalary * 20) as MarSal, > >>>> (A.AprSalary * 20) as AprSal > >>>> From MyTable A > >>>> ) x > >>>> > >>>> -- > >>>> Tom > >>>> > >>>> ---------------------------------------------------- > >>>> Thomas A. Moreau, BSc, PhD, MCSE, MCDBA > >>>> SQL Server MVP > >>>> Columnist, SQL Server Professional > >>>> Toronto, ON Canada > >>>> www.pinpub.com > >>>> . > >>>> "MS User" <sql***@sql.com> wrote in message > >>>> news:utEqCURpFHA.3516@TK2MSFTNGP15.phx.gbl... > >>>> I need to execute a sql > >>>> > >>>> Select (A.JanSalary * 20) as JanSal, > >>>> (A.FebSalary * 20) as FebSal, > >>>> (A.MarSalary * 20) as MarSal, > >>>> (A.AprSalary * 20) as AprSal, > >>>> sum(JanSal + FebSal + MarSal + AprSal) as 'Total' > >>>> From MyTable A > >>>> > >>>> > >>>> Error message - 'Invalid column JanSal,.....' > >>>> > >>>> Question is - How to use the computed column in the same SELECT > >>>> statement ?? > >>>> > >>>> Thanks > >>>> Mike > >>>> > >>>> > >>> > >>> > >> > >> > > > > > > You don't understand how a SELECT statement works. Unless you want to
keep having this kind of problem, you need to learn SQL and how it works. Here is how a SELECT works in SQL ... at least in theory. Real products will optimize things, but the code has to produce the same results. a) Start in the FROM clause and build a working table from all of the joins, unions, intersections, and whatever other table constructors are there. The <table expression> AS <correlation name> option allows you give a name to this working table which you then have to use for the rest of the containing query. b) Go to the WHERE clause and remove rows that do not pass criteria; that is, that do not test to TRUE (i.e. reject UNKNOWN and FALSE). The WHERE clause is applied to the working set in the FROM clause. c) Go to the optional GROUP BY clause, make groups and reduce each group to a single row, replacing the original working table with the new grouped table. The rows of a grouped table must be group characteristics: (1) a grouping column (2) a statistic about the group (i.e. aggregate functions) (3) a function or (4) an expression made up those three items. d) Go to the optional HAVING clause and apply it against the grouped working table; if there was no GROUP BY clause, treat the entire table as one group. e) Go to the SELECT clause and construct the expressions in the list. This means that the scalar subqueries, function calls and expressions in the SELECT are done after all the other clauses are done. The "AS" operator can also give names to expressions in the SELECT list. These new names come into existence all at once, but after the WHERE clause, GROUP BY clause and HAVING clause has been executed; you cannot use them in the SELECT list or the WHERE clause for that reason. If there is a SELECT DISTINCT, then redundant duplicate rows are removed. For purposes of defining a duplicate row, NULLs are treated as matching (just like in the GROUP BY). f) Nested query expressions follow the usual scoping rules you would expect from a block structured language like C, Pascal, Algol, etc. Namely, the innermost queries can reference columns and tables in the queries in which they are contained. g) The ORDER BY clause is part of a cursor, not a query. The result set is passed to the cursor, which can only see the names in the SELECT clause list, and the sorting is done there. The ORDER BY clause cannot have expression in it, or references to other columns because the result set has been converted into a sequential file structure and that is what is being sorted. As you can see, things happen "all at once" in SQL, not "from left to right" as they would in a sequential file/procedural language model. In those languages, these two statements produce different results: READ (a, b, c) FROM File_X; READ (c, a, b) FROM File_X; while these two statements return the same data: SELECT a, b, c FROM Table_X; SELECT c, a, b FROM Table_X; Think about what a confused mess this statement is in the SQL model. SELECT f(c2) AS c1, f(c1) AS c2 FROM Foobar; That is why such nonsense is illegal syntax. >> Question is - How to use the computed column in the same SELECT statement? << See why this is a bad question? All the columns come into existenceall at once. You will need to first get a (derived) table with the computed columns, then you can total them.  |
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